What is the axis x<=+y^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis x<=+y^2

axis

x \leq + y^{2}

y = 0

Solution steps

x \leq y^{2}

Rewrite

x \leq y^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = - x^{2} + 80 x - 700

y = \frac{1}{5} (x - 3)^{2} - 5

y = x^{2} - 2 x + 4

y = x^{2} - 16

y = 9 x^{2} - 4