What is the axis y=(x-9)^2-2 ?

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axis y=(x-9)^2-2

axis

y = (x - 9)^{2} - 2

x = 9

Solution steps

y = (x - 9)^{2} - 2

Rewrite

y = (x - 9)^{2} - 2

in the standard form:

4 \cdot \frac{1}{4} (y - (- 2)) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, - 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 9

y^{2} - 8 x - 16 = 0

(x + 7)^{2} = 5 (y + 3)

x \leq + y^{2}

y = - x^{2} + 80 x - 700

y = \frac{1}{5} (x - 3)^{2} - 5