What is the vertices 4x^2-9y^2=36 ?

The vertices 4x^2-9y^2=36 is (3,0),(-3,0)

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vertices 4x^2-9y^2=36

vertices

4 x^{2} - 9 y^{2} = 36

(3, 0), (- 3, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - 9 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

f (x) = x^{2} - 8

x^{2} - 24 y + 48 = 0

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

3 x^{2} + 8 y = 0