What is the axis (x-h)^2=4p(y-k) ?

The axis (x-h)^2=4p(y-k) is x=h

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axis (x-h)^2=4p(y-k)

axis

(x - h)^{2} = 4 p (y - k)

x = h

Solution steps

(x - h)^{2} = 4 p (y - k)

Rewrite

(x - h)^{2} = 4 p (y - k)

in the standard form:

4 p (y - k) = (x - h)^{2}

Therefore parabola properties are:

(h, k) = (h, k), p = p

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = h

y = x^{2} - x - 6

y^{2} - 10 y - 12 x + 37 = 0

y = - 12 x^{2} - 29 x + 230

y = - \frac{63}{16} + \frac{1}{16} x^{2} - \frac{1}{8} x

y = x^{2} + 8 x - 5