What is the directrix-x^2+2x-3 ?

The directrix-x^2+2x-3 is y=-7/4

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directrix-x^2+2x-3

directrix

- x^{2} + 2 x - 3

y = - \frac{7}{4}

Solution steps

Rewrite

y = - x^{2} + 2 x - 3

in the standard form

4 (- \frac{1}{4}) (y - (- 2)) = (x - 1)^{2}

(h, k) = (1, - 2), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, - 2)

y-coordinate

y = - 2 - p

y = - 2 - (- \frac{1}{4})

Refine

y = - \frac{7}{4}

y^{2} - 6 x + 6 y + 15 = 0

y = - 0.005 x^{2} + x + 5

y = x^{2} - 9 x + 3

- 2 x^{2} - 24 x - 54

x^{2} - 2 x - 3