What is the directrix y^2+2x=0 ?

The directrix y^2+2x=0 is x= 1/2

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directrix y^2+2x=0

directrix

x = \frac{1}{2}

Solution steps

Rewrite

y^{2} + 2 x = 0

in the standard form:

4 (- \frac{1}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{2})

Refine

x = \frac{1}{2}