What is the directrix-8(y+1)=(x-2)^2 ?

The directrix-8(y+1)=(x-2)^2 is y=1

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directrix-8(y+1)=(x-2)^2

directrix

- 8 (y + 1) = (x - 2)^{2}

y = 1

Solution steps

Rewrite

- 8 (y + 1) = (x - 2)^{2}

in the standard form:

4 (- 2) (y - (- 1)) = (x - 2)^{2}

(h, k) = (2, - 1), p = - 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(2, - 1)

y-coordinate

y = - 1 - p

y = - 1 - (- 2)

Refine

y = 1

+ 2 x^{2} + 24 x + 76

y = - 2 x^{2} + 5 x - 6

y^{2} + 2 x = 0

y = - (0.009 (x - 220)^{2} - 220)

y = x^{2} - 10 x - 24