What is the directrix y=7x^2+5 ?

The directrix y=7x^2+5 is y= 139/28

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directrix y=7x^2+5

directrix

y = 7 x^{2} + 5

y = \frac{139}{28}

Solution steps

Rewrite

y = 7 x^{2} + 5

in the standard form:

4 \cdot \frac{1}{28} (y - 5) = (x - 0)^{2}

(h, k) = (0, 5), p = \frac{1}{28}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 5)

y-coordinate

y = 5 - p

y = 5 - \frac{1}{28}

Refine

y = \frac{139}{28}

x^{2} + 3 x + 4

y^{2} = - x

y = (2 x - 1)^{2}

y = - 12 x^{2} - 29 x + 230

y = x^{2} - 5 x 3