What is the directrix y=+x^2+5 ?

The directrix y=+x^2+5 is y= 19/4

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directrix y=+x^2+5

directrix

y = + x^{2} + 5

y = \frac{19}{4}

Solution steps

Rewrite

y = x^{2} + 5

in the standard form:

4 \cdot \frac{1}{4} (y - 5) = (x - 0)^{2}

(h, k) = (0, 5), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 5)

y-coordinate

y = 5 - p

y = 5 - \frac{1}{4}

Refine

y = \frac{19}{4}

y = + x^{2} + 6

x^{2} + 12 x + 38

x = - 3 y^{2}

- 0.2 t^{2} + 2.4 t + 98.6

x^{2} + 2 x - 8 y + 33 = 0