What is the directrix x=(y+3)^2 ?

The directrix x=(y+3)^2 is x=-1/4

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directrix x=(y+3)^2

directrix

x = - \frac{1}{4}

Solution steps

Rewrite

x = (y + 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 3))^{2}

(h, k) = (0, - 3), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, - 3)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{4}

Refine

x = - \frac{1}{4}