What is the directrix x=(y+3)^2 ?

The directrix x=(y+3)^2 is x=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix x=(y+3)^2

directrix

x = (y + 3)^{2}

x = - \frac{1}{4}

Solution steps

Rewrite

x = (y + 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 3))^{2}

(h, k) = (0, - 3), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, - 3)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{4}

Refine

x = - \frac{1}{4}

13 + 4 x - x^{2}

y = s^{2} + 2 s + 2

(x - 11)^{2}

4 P^{2}

x^{2} + 3 x - 16