What is the directrix+x^2-14 ?

The directrix+x^2-14 is y=-57/4

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directrix+x^2-14

directrix

+ x^{2} - 14

y = - \frac{57}{4}

Solution steps

Rewrite

y = x^{2} - 14

in the standard form:

4 \cdot \frac{1}{4} (y - (- 14)) = (x - 0)^{2}

(h, k) = (0, - 14), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 14)

y-coordinate

y = - 14 - p

y = - 14 - \frac{1}{4}

Refine

y = - \frac{57}{4}

x^{2} + 8 x + 3

2 x^{2} - 2 x - 1

- x^{2} + 3 x + 7

(x - 6)^{2}

(x - 2)^{2} = 2 (y + 2)