What is the directrix 3x-3x^2 ?

The directrix 3x-3x^2 is y= 5/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix 3x-3x^2

directrix

y = \frac{5}{6}

Solution steps

Rewrite

y = 3 x - 3 x^{2}

in the standard form

4 (- \frac{1}{12}) (y - \frac{3}{4}) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, \frac{3}{4}), p = - \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{2}, \frac{3}{4})

y-coordinate

y = \frac{3}{4} - p

y = \frac{3}{4} - (- \frac{1}{12})

Refine

y = \frac{5}{6}