What is the directrix 6x^2+7x-3 ?

The directrix 6x^2+7x-3 is y=-61/12

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directrix 6x^2+7x-3

directrix

y = - \frac{61}{12}

Solution steps

Rewrite

y = 6 x^{2} + 7 x - 3

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{121}{24})) = (x - (- \frac{7}{12}))^{2}

(h, k) = (- \frac{7}{12}, - \frac{121}{24}), p = \frac{1}{24}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{7}{12}, - \frac{121}{24})

y-coordinate

y = - \frac{121}{24} - p

y = - \frac{121}{24} - \frac{1}{24}

Refine

y = - \frac{61}{12}