What is -1/3 (x-3)=(y+5)^2 ?

The solution to -1/3 (x-3)=(y+5)^2 is Parabola with (h,k)=(3,-5),p=-1/12

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-1/3 (x-3)=(y+5)^2

- \frac{1}{3} (x - 3) = (y + 5)^{2}

(h, k) = (3, - 5), p = - \frac{1}{12}

Solution steps

- \frac{1}{3} (x - 3) = (y + 5)^{2}

Rewrite

- \frac{1}{3} (x - 3) = (y + 5)^{2}

in the standard form:

4 (- \frac{1}{12}) (x - 3) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (3, - 5), p = - \frac{1}{12}

y, x^{2} - y^{2} = 0

25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

(x - 1)^{2} + (y - 2)^{2} = 4

y^{2} = - 36 x

x^{2} + 4 y^{2} = 36

What is -1/3 (x-3)=(y+5)^2 ?
The solution to -1/3 (x-3)=(y+5)^2 is Parabola with (h,k)=(3,-5),p=-1/12