What is the directrix-x^2-3x-2 ?

The directrix-x^2-3x-2 is y= 1/2

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directrix-x^2-3x-2

directrix

y = \frac{1}{2}

Solution steps

Rewrite

y = - x^{2} - 3 x - 2

in the standard form

4 (- \frac{1}{4}) (y - \frac{1}{4}) = (x - (- \frac{3}{2}))^{2}

(h, k) = (- \frac{3}{2}, \frac{1}{4}), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{3}{2}, \frac{1}{4})

y-coordinate

y = \frac{1}{4} - p

y = \frac{1}{4} - (- \frac{1}{4})

Refine

y = \frac{1}{2}