What is the directrix 5x^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix 5x^2

directrix

y = - \frac{1}{20}

Solution steps

Rewrite

y = 5 x^{2}

in the standard form:

4 \cdot \frac{1}{20} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{20}

Refine

y = - \frac{1}{20}