What is the directrix (x-3)^2+1 ?

The directrix (x-3)^2+1 is y= 3/4

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directrix (x-3)^2+1

directrix

y = \frac{3}{4}

Solution steps

Rewrite

y = (x - 3)^{2} + 1

in the standard form:

4 \cdot \frac{1}{4} (y - 1) = (x - 3)^{2}

(h, k) = (3, 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, 1)

y-coordinate

y = 1 - p

y = 1 - \frac{1}{4}

Refine

y = \frac{3}{4}