What is the directrix y=2x^2+3pi ?

The directrix y=2x^2+3pi is y=3pi-1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix y=2x^2+3pi

directrix

y = 3 π - \frac{1}{8}

Solution steps

Rewrite

y = 2 x^{2} + 3 π

in the standard form:

4 \cdot \frac{1}{8} (y - 3 π) = (x - 0)^{2}

(h, k) = (0, 3 π), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 3 π)

y-coordinate

y = 3 π - p

y = 3 π - \frac{1}{8}