What is the directrix x^2-2x-4y+13=0 ?

The directrix x^2-2x-4y+13=0 is y=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix x^2-2x-4y+13=0

directrix

y = 2

Solution steps

Rewrite

x^{2} - 2 x - 4 y + 13 = 0

in the standard form

4 \cdot 1 \cdot (y - 3) = (x - 1)^{2}

(h, k) = (1, 3), p = 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, 3)

y-coordinate

y = 3 - p

y = 3 - 1

Refine

y = 2