What is the directrix y^2-4y-8x-12=0 ?

The directrix y^2-4y-8x-12=0 is x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix y^2-4y-8x-12=0

directrix

x = - 4

Solution steps

Rewrite

y^{2} - 4 y - 8 x - 12 = 0

in the standard form

4 \cdot 2 (x - (- 2)) = (y - 2)^{2}

(h, k) = (- 2, 2), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 2)

x-coordinate

x = - 2 - p

x = - 2 - 2

Refine

x = - 4