What is the directrix y^2+16x=0 ?

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directrix y^2+16x=0

directrix

y^{2} + 16 x = 0

x = 4

Solution steps

Rewrite

y^{2} + 16 x = 0

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 4)

Refine

x = 4

y^{2} + 28 x = 0

y = 4 x^{2} - 24 x + 31

y = - x^{2} + 4 x

y^{2} + 4 x - 14 y = - 53

y = 6 x^{2} + 12 x