What is the directrix x^2+2x-16y+65=0 ?

The directrix x^2+2x-16y+65=0 is y=0

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directrix x^2+2x-16y+65=0

directrix

y = 0

Solution steps

Rewrite

x^{2} + 2 x - 16 y + 65 = 0

in the standard form

4 \cdot 4 (y - 4) = (x - (- 1))^{2}

(h, k) = (- 1, 4), p = 4

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1, 4)

y-coordinate

y = 4 - p

y = 4 - 4

Refine

y = 0