What is the directrix-8(x-5)=(y+1)^2 ?

The directrix-8(x-5)=(y+1)^2 is x=7

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directrix-8(x-5)=(y+1)^2

directrix

- 8 (x - 5) = (y + 1)^{2}

x = 7

Solution steps

Rewrite

- 8 (x - 5) = (y + 1)^{2}

in the standard form:

4 (- 2) (x - 5) = (y - (- 1))^{2}

(h, k) = (5, - 1), p = - 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(5, - 1)

x-coordinate

x = 5 - p

x = 5 - (- 2)

Refine

x = 7

y = (x - 2)^{2} + 3

y^{2} - 8 y + 4 x = 0

x^{2} + 4 x + 6 y - 2 = 0

48 x - 6 x^{2}

2 x^{2} - x