What is the foci (x^2)/7-(y^2)/2 =1 ?

The foci (x^2)/7-(y^2)/2 =1 is (3,0),(-3,0)

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foci (x^2)/7-(y^2)/2 =1

foci

\frac{x ^{2}}{7} - \frac{y ^{2}}{2} = 1

(3, 0), (- 3, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{7} - \frac{y ^{2}}{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 2^{2} : 3

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

x^{2} + y^{2} = 18

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

x^{2} - 12 y - 6 x + 5 = 0

x^{2} + y^{2} = 64

What is the foci (x^2)/7-(y^2)/2 =1 ?
The foci (x^2)/7-(y^2)/2 =1 is (3,0),(-3,0)