What is the directrix x<= y^2 ?

The directrix x<= y^2 is x=-1/4

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directrix x<= y^2

directrix

x \leq y^{2}

x = - \frac{1}{4}

Solution steps

Rewrite

x \leq y^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{4}

Refine

x = - \frac{1}{4}

y^{2} = x - 3

y = x^{2} - 4 x - 4

+ y^{2} - y - x + 1 = 0

y = - x^{2} - 6 x - 7

2 x^{2} - 13 x - 7