What is the directrix y=x^2+2x+4 ?

The directrix y=x^2+2x+4 is y= 11/4

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directrix y=x^2+2x+4

directrix

y = x^{2} + 2 x + 4

y = \frac{11}{4}

Solution steps

Rewrite

y = x^{2} + 2 x + 4

in the standard form

4 \cdot \frac{1}{4} (y - 3) = (x - (- 1))^{2}

(h, k) = (- 1, 3), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1, 3)

y-coordinate

y = 3 - p

y = 3 - \frac{1}{4}

Refine

y = \frac{11}{4}

y = 5 x^{2}

3 x^{2} - x + 5

x^{2} + 6 y = 0

y = 2 x^{2} - 19 x + 9

- 2 x^{2}