What is the directrix y^2+4y+8x-12=0 ?

The directrix y^2+4y+8x-12=0 is x=4

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directrix y^2+4y+8x-12=0

directrix

y^{2} + 4 y + 8 x - 12 = 0

x = 4

Solution steps

Rewrite

y^{2} + 4 y + 8 x - 12 = 0

in the standard form

4 (- 2) (x - 2) = (y - (- 2))^{2}

(h, k) = (2, - 2), p = - 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 2)

x-coordinate

x = 2 - p

x = 2 - (- 2)

Refine

x = 4

4 x^{2} - 8 x + 2 y = 5

88 x - 16 x^{2} - 112

- 16 t^{2} + 60 t + 3

\frac{x ^{2} - 4 x - 4}{2}

y = \frac{x ^{4} - x ^{2} - 2 x - 1}{x ^{2} - x - 1}