What is the directrix x= 1/8 y^2 ?

The directrix x= 1/8 y^2 is x=-2

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directrix x= 1/8 y^2

directrix

x = \frac{1}{8} y^{2}

x = - 2

Solution steps

Rewrite

x = \frac{1}{8} y^{2}

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 2

Refine

x = - 2

y = 2 x^{2} + 6 x + 10

(x - 2)^{2} = - (y - 1)

y = x^{2} - 2 x + 5

y = - 3 x^{2} + 6 x - 1

X^{2} - 5 X - 24