What is (x^2)/(144)-(y^2)/(25)=1 ?

The solution to (x^2)/(144)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=12,b=5

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(x^2)/(144)-(y^2)/(25)=1

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 12, b = 5

Solution steps

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 2 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 12, b = 5

f (x) = 2 x^{2}

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

(x - 1)^{2} = - 4 (y - 2)

\frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

x^{2} + \frac{y ^{2}}{49} = 1

What is (x^2)/(144)-(y^2)/(25)=1 ?
The solution to (x^2)/(144)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=12,b=5