What is the directrix-x^2+14x-45 ?

The directrix-x^2+14x-45 is y= 17/4

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directrix-x^2+14x-45

directrix

- x^{2} + 14 x - 45

y = \frac{17}{4}

Solution steps

Rewrite

y = - x^{2} + 14 x - 45

in the standard form

4 (- \frac{1}{4}) (y - 4) = (x - 7)^{2}

(h, k) = (7, 4), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(7, 4)

y-coordinate

y = 4 - p

y = 4 - (- \frac{1}{4})

Refine

y = \frac{17}{4}

y = x^{2} + 5 x + 6

y^{2} = 6 x

- 4 x^{2} + 2 x + 2

(y - 2)^{2} = 8 (x - 1)

y = 4 x + 4 x - 2 + x^{2} - 3