What is the directrix y=12x^2-72x+77 ?

The directrix y=12x^2-72x+77 is y=-1489/48

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directrix y=12x^2-72x+77

directrix

y = 12 x^{2} - 72 x + 77

y = - \frac{1489}{48}

Solution steps

Rewrite

y = 12 x^{2} - 72 x + 77

in the standard form

4 \cdot \frac{1}{48} (y - (- 31)) = (x - 3)^{2}

(h, k) = (3, - 31), p = \frac{1}{48}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, - 31)

y-coordinate

y = - 31 - p

y = - 31 - \frac{1}{48}

Refine

y = - \frac{1489}{48}

4 - x - x^{2}

y = - 7 (x - 8)^{2} + 6

y = x^{2} - 9 x + 20

x^{2} - 6 x + 5 y = 34

y = (x - 4)^{2} - 9

What is the directrix y=12x^2-72x+77 ?
The directrix y=12x^2-72x+77 is y=-1489/48