What is the directrix y= 1/8 x^2 ?

The directrix y= 1/8 x^2 is y=-2

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directrix y= 1/8 x^2

directrix

y = \frac{1}{8} x^{2}

y = - 2

Solution steps

Rewrite

y = \frac{1}{8} x^{2}

in the standard form:

4 \cdot 2 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 2

Refine

y = - 2

- 2 x^{2} + 5 x - 6

4 x^{2} - 20 x - 24 y + 97 = 0

\frac{6 x}{7} \frac{4 x}{3}

x^{2} - x - 6

y = (x + 4)^{2}