What is the directrix y^2=x+1 ?

The directrix y^2=x+1 is x=-5/4

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directrix y^2=x+1

directrix

y^{2} = x + 1

x = - \frac{5}{4}

Solution steps

Rewrite

y^{2} = x + 1

in the standard form:

4 \cdot \frac{1}{4} (x - (- 1)) = (y - 0)^{2}

(h, k) = (- 1, 0), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 1, 0)

x-coordinate

x = - 1 - p

x = - 1 - \frac{1}{4}

Refine

x = - \frac{5}{4}

y = \frac{x ^{4} - 1}{x ^{2} - 1}

(x - 2) (x + 1)

5 x^{2} + 30 x + 24 y = 51

x^{2} - 2 x - 4 y + 9 = 0

\frac{- 3 x ^{2} - 2 x + 6}{5}