de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

leitkurve 4x^2

Lösung

leitkurve

4 x^{2}

Lösung

y = - \frac{1}{16}

Schritte zur Lösung

Rewrite

y = 4 x^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{16}

Fasse zusammen

y = - \frac{1}{16}

Graph

Beliebte Beispiele

leitkurve y=4x^2-4x^1

d i rec t r i x y = 4 x^{2} - 4 x^{1}

leitkurve y=3x^2-x+5

d i rec t r i x y = 3 x^{2} - x + 5

leitkurve x=y^2-y-42

d i rec t r i x x = y^{2} - y - 42

leitkurve x^2-4x-8y+2=0

d i rec t r i x x^{2} - 4 x - 8 y + 2 = 0

leitkurve (3x-4)(4x-3)-2x

d i rec t r i x (3 x - 4) (4 x - 3) - 2 x