en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=x^2+2x+1

Solution

foci

y = x^{2} + 2 x + 1

Solution

(- 1, \frac{1}{4})

Solution steps

Rewrite

y = x^{2} + 2 x + 1

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - (- 1))^{2}

(h, k) = (- 1, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, 0)

along the y-axis

(- 1, 0 + p)

= (- 1, 0 + \frac{1}{4})

Refine

(- 1, \frac{1}{4})

Popular Examples

foci x=3(y-2)^2-7 foci

x = 3 (y - 2)^{2} - 7

foci 3x^2+2x+6 foci

3 x^{2} + 2 x + 6

foci 1/8 x^2-y=0 foci

\frac{1}{8} x^{2} - y = 0

foci-x^2+4y-44=-8x foci

- x^{2} + 4 y - 44 = - 8 x

foci-x^2-2x+3 foci

- x^{2} - 2 x + 3

Frequently Asked Questions (FAQ)

What is the foci y=x^2+2x+1 ?
The foci y=x^2+2x+1 is (-1, 1/4)