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Popular >

foci y^2+x+y=0

Solution

foci

y^{2} + x + y = 0

Solution

(0, - \frac{1}{2})

Solution steps

Rewrite

y^{2} + x + y = 0

in the standard form

4 (- \frac{1}{4}) (x - \frac{1}{4}) = (y - (- \frac{1}{2}))^{2}

(h, k) = (\frac{1}{4}, - \frac{1}{2}), p = - \frac{1}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(\frac{1}{4}, - \frac{1}{2})

along the x-axis

(\frac{1}{4} + p, - \frac{1}{2})

= (\frac{1}{4} + (- \frac{1}{4}), - \frac{1}{2})

Refine

(0, - \frac{1}{2})

Popular Examples

foci y=(x+1)(x+2)foci

y = (x + 1) (x + 2)

foci 3x^2-16x+5 foci

3 x^{2} - 16 x + 5

foci y^2-12y+6x+36=0 foci

y^{2} - 12 y + 6 x + 36 = 0

foci x^2-6x-20y-11=0 foci

x^{2} - 6 x - 20 y - 11 = 0

foci y=3x^2-36x+81 foci

y = 3 x^{2} - 36 x + 81

Frequently Asked Questions (FAQ)

What is the foci y^2+x+y=0 ?
The foci y^2+x+y=0 is (0,-1/2)