What is the foci-0.1x^2+1.2x+98.6 ?

The foci-0.1x^2+1.2x+98.6 is (6,99.7)

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foci-0.1x^2+1.2x+98.6

foci

- 0.1 x^{2} + 1.2 x + 98.6

(6, 99.7)

Solution steps

Rewrite

y = - 0.1 x^{2} + 1.2 x + 98.6

in the standard form

4 (- 2.5) (y - 102.2) = (x - 6)^{2}

(h, k) = (6, 102.2), p = - 2.5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(6, 102.2)

along the y-axis

(6, 102.2 + p)

= (6, 102.2 + (- 2.5))

Refine

(6, 99.7)

y^{2} - 8 x - 6 y - 3 = 0

(x - 2)^{2} = 2 y + 1

x = 3 - 5 (y + 1)^{2}

y = x^{2} - 6 x + 11

y = (x + 1)^{2} + 1