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Popular >

foci x^2+2x-7

Solution

foci

x^{2} + 2 x - 7

Solution

(- 1, - \frac{31}{4})

Solution steps

Rewrite

y = x^{2} + 2 x - 7

in the standard form

4 \cdot \frac{1}{4} (y - (- 8)) = (x - (- 1))^{2}

(h, k) = (- 1, - 8), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, - 8)

along the y-axis

(- 1, - 8 + p)

= (- 1, - 8 + \frac{1}{4})

Refine

(- 1, - \frac{31}{4})

Popular Examples

foci (x-1)^2=4(y-2)foci

(x - 1)^{2} = 4 (y - 2)

foci y=+5-x^2 foci

y = + 5 - x^{2}

foci y=(0.5-x)^2 foci

y = (0.5 - x)^{2}

foci 25x^2-4 foci

25 x^{2} - 4

foci 2x^2-8y=6x^2+20y foci

2 x^{2} - 8 y = 6 x^{2} + 20 y

Frequently Asked Questions (FAQ)

What is the foci x^2+2x-7 ?
The foci x^2+2x-7 is (-1,-31/4)