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Beliebt Geometry >

foki 10x^2-19x+5

Lösung

foki

10 x^{2} - 19 x + 5

Lösung

(\frac{19}{20}, - 4)

Schritte zur Lösung

Rewrite

y = 10 x^{2} - 19 x + 5

in the standard form

4 \cdot \frac{1}{40} (y - (- \frac{161}{40})) = (x - \frac{19}{20})^{2}

(h, k) = (\frac{19}{20}, - \frac{161}{40}), p = \frac{1}{40}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{19}{20}, - \frac{161}{40})

along the y-axis

(\frac{19}{20}, - \frac{161}{40} + p)

= (\frac{19}{20}, - \frac{161}{40} + \frac{1}{40})

Fasse zusammen

(\frac{19}{20}, - 4)

Graph

Beliebte Beispiele

foki+(1/2 x-1)^2-2

f oc i + (\frac{1}{2} x - 1)^{2} - 2

f oc i x^{2} + x - 4

foki (x+6)^2=9(y-1)

f oc i (x + 6)^{2} = 9 (y - 1)

foki x^2-2x-6y-5=0

f oc i x^{2} - 2 x - 6 y - 5 = 0

f oc i 81 y^{2}