What is the foci y=16x^2-25 ?

The foci y=16x^2-25 is (0,-1599/64)

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foci y=16x^2-25

foci

y = 16 x^{2} - 25

(0, - \frac{1599}{64})

Solution steps

Rewrite

y = 16 x^{2} - 25

in the standard form:

4 \cdot \frac{1}{64} (y - (- 25)) = (x - 0)^{2}

(h, k) = (0, - 25), p = \frac{1}{64}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 25)

along the y-axis

(0, - 25 + p)

= (0, - 25 + \frac{1}{64})

Refine

(0, - \frac{1599}{64})

+ 2 x^{2} - 3 x - 1

y = \frac{1}{2} x^{2} - 2

2 x^{2} - 5 x + 1

- x^{2} - 6 x - 8

- 16 x^{2} + 136 x + 57