What is the foci (6x-5)^2 ?

The foci (6x-5)^2 is (5/6 , 1/144)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (6x-5)^2

foci

(6 x - 5)^{2}

(\frac{5}{6}, \frac{1}{144})

Solution steps

Rewrite

y = (6 x - 5)^{2}

in the standard form:

4 \cdot \frac{1}{144} (y - 0) = (x - \frac{5}{6})^{2}

(h, k) = (\frac{5}{6}, 0), p = \frac{1}{144}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{5}{6}, 0)

along the y-axis

(\frac{5}{6}, 0 + p)

= (\frac{5}{6}, 0 + \frac{1}{144})

Refine

(\frac{5}{6}, \frac{1}{144})

y = - \frac{1}{4} x^{2}

y = 9 x^{2} + 24 x + 16

x^{2} - 5 y = 0

x^{2} + 6 x - 1

y = - (x + 3)^{2} - 1