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Popular >

foci-y^2=6y+x

Solution

foci

- y^{2} = 6 y + x

Solution

(\frac{35}{4}, - 3)

Solution steps

Rewrite

- y^{2} = 6 y + x

in the standard form

4 (- \frac{1}{4}) (x - 9) = (y - (- 3))^{2}

(h, k) = (9, - 3), p = - \frac{1}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(9, - 3)

along the x-axis

(9 + p, - 3)

= (9 + (- \frac{1}{4}), - 3)

Refine

(\frac{35}{4}, - 3)

Popular Examples

foci (y+1)^2=16(x-3)foci

(y + 1)^{2} = 16 (x - 3)

foci (x+1)(x-5)foci

(x + 1) (x - 5)

foci (x-6)^2=1(y-6)foci

(x - 6)^{2} = 1 (y - 6)

foci-x^2-2 foci

- x^{2} - 2

foci 3x^2+8y=0 foci

3 x^{2} + 8 y = 0

Frequently Asked Questions (FAQ)

What is the foci-y^2=6y+x ?
The foci-y^2=6y+x is (35/4 ,-3)