What is the foci (x+9)^2=-40(y-7) ?

The foci (x+9)^2=-40(y-7) is (-9,-3)

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foci (x+9)^2=-40(y-7)

foci

(x + 9)^{2} = - 40 (y - 7)

(- 9, - 3)

Solution steps

Rewrite

(x + 9)^{2} = - 40 (y - 7)

in the standard form:

4 (- 10) (y - 7) = (x - (- 9))^{2}

(h, k) = (- 9, 7), p = - 10

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 9, 7)

along the y-axis

(- 9, 7 + p)

= (- 9, 7 + (- 10))

Refine

(- 9, - 3)

y = x^{2} - 14 x - 49

4 x - x^{2}

\frac{1}{2} (1 - 2 y - y^{2})

(x + 7)^{2}

x = 3 (y - 3)^{2} - 1