What is the foci y^2=-25x ?

The foci y^2=-25x is (-25/4 ,0)

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foci y^2=-25x

foci

y^{2} = - 25 x

(- \frac{25}{4}, 0)

Solution steps

Rewrite

y^{2} = - 25 x

in the standard form:

4 (- \frac{25}{4}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{25}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{25}{4}), 0)

Refine

(- \frac{25}{4}, 0)

(x + 2)^{2} = 20 (y - 5)

y^{2} = - x

x^{2} + 2 x - y = 3

4 x^{2} + 48 y + 12 x = 159

y = 2 x^{2} + 5 x - 3