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Popular >

foci x^2=-16y

Solution

foci

x^{2} = - 16 y

Solution

(0, - 4)

Solution steps

Rewrite

x^{2} = - 16 y

in the standard form:

4 (- 4) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- 4))

Refine

(0, - 4)

Popular Examples

x^{2}

foci ((x-3)^2)/5+((y-1)^2)/(15)=1 foci

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

foci (x^2)/(100)+(y^2)/(64)=1 foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

foci (x^2)/4+(y^2)/(16)=1 foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

foci 3x^2+2y^2=6 foci

3 x^{2} + 2 y^{2} = 6

Frequently Asked Questions (FAQ)

What is the foci x^2=-16y ?
The foci x^2=-16y is (0,-4)