What is the foci 25x^2-10x-200y-119=0 ?

The foci 25x^2-10x-200y-119=0 is (1/5 , 7/5)

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foci 25x^2-10x-200y-119=0

foci

25 x^{2} - 10 x - 200 y - 119 = 0

(\frac{1}{5}, \frac{7}{5})

Solution steps

Rewrite

25 x^{2} - 10 x - 200 y - 119 = 0

in the standard form

4 \cdot 2 (y - (- \frac{3}{5})) = (x - \frac{1}{5})^{2}

(h, k) = (\frac{1}{5}, - \frac{3}{5}), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{1}{5}, - \frac{3}{5})

along the y-axis

(\frac{1}{5}, - \frac{3}{5} + p)

= (\frac{1}{5}, - \frac{3}{5} + 2)

Refine

(\frac{1}{5}, \frac{7}{5})

2 π r^{2} + 16 π r

x^{2} - 4 x - 8 y - 12 = 0

(x - 6)^{2} = - 4 y

4 t^{2} + 1

t^{2} + 2 t - 48

What is the foci 25x^2-10x-200y-119=0 ?
The foci 25x^2-10x-200y-119=0 is (1/5 , 7/5)