What is the foci y^2-12x-2y+25=0 ?

The foci y^2-12x-2y+25=0 is (5,1)

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foci y^2-12x-2y+25=0

foci

y^{2} - 12 x - 2 y + 25 = 0

(5, 1)

Solution steps

Rewrite

y^{2} - 12 x - 2 y + 25 = 0

in the standard form

4 \cdot 3 (x - 2) = (y - 1)^{2}

(h, k) = (2, 1), p = 3

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(2, 1)

along the x-axis

(2 + p, 1)

= (2 + 3, 1)

Refine

(5, 1)

- x^{2} + 4 x + 5

x = - 3 y^{2}

(y - 7)^{2} = - 12 (x + 1)

x^{2} - 6 x - 12 y + 21 = 0

x^{2} - 15 x