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Popular >

foci y=7x^2

Solution

foci

y = 7 x^{2}

Solution

(0, \frac{1}{28})

Solution steps

Rewrite

y = 7 x^{2}

in the standard form:

4 \cdot \frac{1}{28} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{28}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{28})

Refine

(0, \frac{1}{28})

Popular Examples

foci y=x^2+2x+4 foci

y = x^{2} + 2 x + 4

foci y^2+2y+1=-2x+4 foci

y^{2} + 2 y + 1 = - 2 x + 4

foci (y-3)^2=-8(x+2)foci

(y - 3)^{2} = - 8 (x + 2)

foci y=+x^2+6x foci

y = + x^{2} + 6 x

foci y=-x^2+14x+49 foci

y = - x^{2} + 14 x + 49

Frequently Asked Questions (FAQ)

What is the foci y=7x^2 ?
The foci y=7x^2 is (0, 1/28)