What is the foci y^2+8x-4y+20=0 ?

The foci y^2+8x-4y+20=0 is (-4,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2+8x-4y+20=0

foci

y^{2} + 8 x - 4 y + 20 = 0

(- 4, 2)

Solution steps

Rewrite

y^{2} + 8 x - 4 y + 20 = 0

in the standard form

4 (- 2) (x - (- 2)) = (y - 2)^{2}

(h, k) = (- 2, 2), p = - 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 2, 2)

along the x-axis

(- 2 + p, 2)

= (- 2 + (- 2), 2)

Refine

(- 4, 2)

x^{2} + 6 x - 7

x^{2} + x

y^{2} + 12 y - 4 x + 48 = 0

x^{2} + 1

x^{2} + 4