What is the foci (x-h)^2=4p(y-k) ?

The foci (x-h)^2=4p(y-k) is (h,k+p)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x-h)^2=4p(y-k)

foci

(x - h)^{2} = 4 p (y - k)

(h, k + p)

Solution steps

Rewrite

(x - h)^{2} = 4 p (y - k)

in the standard form:

4 p (y - k) = (x - h)^{2}

(h, k) = (h, k), p = p

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(h, k)

along the y-axis

(h, k + p)

= (h, k + p)

\frac{x ^{2}}{3}

y^{2} - 4 y + 12 x - 8 = 0

4 - x^{2}

6 x^{2} - 4

4 y^{2} = x